It can be proved that the projectile takes equal time (V0sin g to come back to ground from its maximum height. Part b: Find total time aloft. We will cover here couple of equations like the the projectile path equation equation for time to reach maximum height total time maximum height of a projectile and equation for horizontal range of a projectile. Gravity or Gravitational force applied by the earth. Just remember velocity is a vector and will have both x and y components.

Laws Of Physics,

And this force directs vertically downwards pointing to the centre of the earth. Hangouts, keep, earth, even more from Google, hidden fields. If not acted upon by an unbalanced force, "an object in motion will.". Due to the absence of horizontal forces, a projectile remains in motion with a constant horizontal velocity. Part c: Find range R To find the range, we need to know the initial velocity in the x direction. To find these positions, we will use the same equation: d v0t at2 First, lets do the horizontal position. Gravity causes a vertical acceleration. R 106.1 m/s.6s R 2291.8 m The projectile landed 2291.8 meters from the canon.